mysql_field_name

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_field_name — Podaje nazwę danego pola w wyniku

Opis

string mysql_field_name ( resource $wynik , int $indeks_pola )

mysql_field_name() zwraca nazwę danego pola. wynik musi być poprawnym identyfikatorem wyniku, a indeks_pola powinien zawierać liczbowy indeks pola.

Informacja: indeks_pola liczy się od 0.
Indeksem trzeciego pola będzie liczba 2, czwartego 3 i tak dalej...

Example #1 mysql_field_name()


<?php
/* Tabela składa się z trzech pól: 
 *   id_uzytkownika
 *   nazwa_uzytkownika
 *   haslo
 */
$link = mysql_connect('localhost', 'uzytkownik', 'haslo');  
mysql_select_db($dbname, $link)  
    or die("Nie można otworzyć bazy $dbname");  
$res = mysql_query("select * from users", $link);  
echo mysql_field_name($res, 0) . "\n";
echo mysql_field_name($res, 2);
?>

Powyższy przykład da następujący wynik:

id_uzytkownika
haslo

Aby zachować zgodność z poprzednimi wersjami, można użyć również mysql_fieldname(). Jest to jednak niezalecane.

mysql_field_seek

mysql_field_len

Last updated: Fri, 28 Nov 2008

add a note User Contributed Notes
mysql_field_name

anonymous at site dot com
09-Mar-2008 07:13


This function is slightly stupid to be honest, why not just make an array of field names... You could consolidate the two of these functions that way and it makes it a lot easier to list them when your script is dynamic.



<?php



    function mysql_field_array( $query ) {

    

        $field = mysql_num_fields( $query );

    

        for ( $i = 0; $i < $field; $i++ ) {

        

            $names[] = mysql_field_name( $query, $i );

        

        }

        

        return $names;

    

    }

    

    // Examples of use

    

    $fields = mysql_field_array( $query );

    

    // Show name of column 3

    

    echo $fields[3];

    

    // Show them all

    

    echo implode( ', ', $fields[3] );

    

     // Count them - easy equivelant to 'mysql_num_fields'

    

    echo count( $fields );



?>

blackjackdevel at gmail dot com
13-Nov-2007 04:13


Strangely using an aproach like this:

$res=mysql_query("SELECT * FROM `orders`",$conec) or die (mysql_error());



$fields = mysql_num_fields($res);

$out="";

for ($i = 0; $i < $fields; $i++) {

    $fname=mysql_field_name($res, $i);



}



 Outputted the E_Warning:

Warning: mysql_field_name() [function.mysql-field-name]: Field N is invalid for MySQL result index 



 With a lot of different number at N. But expliciting all fields instead of *. Didn't outputted the error.



 It maybe a caracteristic of this mysql database(it is from a open source application) because i never saw this in my own databases. Anyway hope this help if someone face the same strange situation

matteo.cisilino[no_more]cisilino[spm]com
09-Jan-2007 08:54


james, why make so difficult when it's very simple :\



$numberfields = mysql_num_fields($res_gb);



   for ($i=0; $i<$numberfields ; $i++ ) {

       $var = mysql_field_name($res_gb, $i);

       $row_title .= $var;

   }



echo $row_title;

janezr at jcn dot si
19-Oct-2005 07:18


This is another variant of displaying all columns of a query result, but with a simplified while loop.



<?

$query="select * from user";

$result=mysql_query($query);

$numfields = mysql_num_fields($result);



echo "<table>\n<tr>";



for ($i=0; $i < $numfields; $i++) // Header

{ echo '<th>'.mysql_field_name($result, $i).'</th>'; }



echo "</tr>\n";



while ($row = mysql_fetch_row($result)) // Data

{ echo '<tr><td>'.implode($row,'</td><td>')."</td></tr>\n"; }



echo "</table>\n"

?>

clinnenb at hotmail dot com
05-Aug-2005 08:19


The following will create a PHP array, $array, containing the MySQL query results with array indexes of the same name as field names returned by the MySQL query.



while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {

    $i=0;

    foreach ($line as $col_value) {

        $field=mysql_field_name($result,$i);

        $array[$field] = $col_value;

        $i++;

    }

}

jimharris at blueyonder dot co dot uk
20-Dec-2004 06:28


The code in the last comment has an obvious mistake in the for loop expression.  The correct expression in the for-loop is $x<$y rather than $x<=$y...



$result = mysql_query($sql,$conn) or die(mysql_error());

$rowcount=mysql_num_rows($result);

$y=mysql_num_fields($result);

for ($x=0; $x<$y; $x++) {

   echo = mysql_field_name($result, $x).'<br>';

}

colin dot truran at shiftf7 dot com
17-Dec-2004 04:44


T simply itterate through all the field names on a result set try using this.



$result = mysql_query($sql,$conn) or die(mysql_error());

$rowcount=mysql_num_rows($result);

$y=mysql_num_fields($result);

for ($x=0; $x<=$y; $x++) {

    echo = mysql_field_name($result, $x).'<br>';

}



This is useful if you have a result set that joins several tables dynamicaly and you are never sure what all the fields will be when you come to display them.



I suggest you place this within a loop through your result rows and include a field flag check  around the echo to only show certain data types like this.



$y=mysql_num_fields($result);

while ($row=mysql_fetch_array($result)) {

  for ($x=0; $x<=$y; $x++) {

    $fieldname=mysql_field_name($result,$x);

    $fieldtype=mysql_field_type($result, $x);

    if ($fieldtype=='string' && $row[$fieldname]!='')    

       echo $row[$fieldname].' , ';

   }

   echo '<br>';

}

aaronp123 att yahoo dott comm
21-Feb-2003 06:27


You could probably elaborate on this by sending a full sql query to this function...but I titled it simple_query() because it doesn't really allow for joins.  Never the less, if you want to get a quick array full of a single row result set this is painless:



function simple_query($table_name, $key_col, $key_val) {

    // open the db

    $db_link = my_sql_link();

    // query table using key col/val

    $db_rs = mysql_query("SELECT * FROM $table_name WHERE $key_col = $key_val", $db_link);

    $num_fields = mysql_num_fields($db_rs);

    if ($num_fields) {

        // first (and only) row

        $row = mysql_fetch_assoc($db_rs);

        // load up array

        for ($i = 0; $i < $num_fields; $i++) {

            $simple_q[mysql_field_name($db_rs, $i)] = $row[mysql_field_name($db_rs, $i)];

        }

        // and return

        return $simple_q;

    } else {

        // no rows

        return false;

    }

    mysql_free_result($db_rs);

}



**Please note that my_sql_link() is just a function I have to open up a my sql connection.**

jason dot chambes at phishie dot net
20-Feb-2003 06:07


<?

/*

    By simply calling the searchtable() function

    with these variables it will serach the desired

    database and procude a table for each field that

    there is a match.

*/



function searchtable($host,$user,$pass,$database,$tablename,$userquery)

{

    $link   = mysql_connect($host, $user, $pass) or die("Could not connect: " . mysql_error());

    $db     = mysql_select_db($database, $link) or die(mysql_error());

    $fields = mysql_list_fields($database, $tablename, $link);

    $cols   = mysql_num_fields($fields);



    for ($i = 1; $i < $cols; $i++) {

        $allfields[] = mysql_field_name($fields, $i);

    }

    foreach ($allfields as $myfield) {

        $result = mysql_query("SELECT * FROM $tablename WHERE $myfield like '%$userquery%' ");

        if (mysql_num_rows($result) > 0){

            echo "<h3>search <i>$database</i> for <i>$userquery</i>, found match(es) in <i>$myfield</i>: </h3>\n";

            echo "<table border=1 align=\"center\">\n\t<tr>\n";

            for ($i = 1; $i < $cols; $i++) {

                echo "\t\t<th";

                if ($myfield == mysql_field_name($fields, $i)){

                    echo " bgcolor=\"orange\"> ";

                } else {

                    echo ">";

                }

                echo mysql_field_name($fields, $i) . "</th>\n";

            }

            echo "\t</tr>\n";

            $myrow = mysql_fetch_array($result);

            do {

                echo "\t<tr>\n";

                for ($i = 1; $i < $cols; $i++){

                    echo "\t\t<td> $myrow[$i] &nbsp;</td>\n";

                }

                echo "\t</tr>\n";

            } while ($myrow = mysql_fetch_array($result));

            echo "</table>\n";

        }

    }

}



searchtable($host,$user,$pass,$database,$tablename,$userquery);

?>

matt at iwdt dot net
23-Sep-2001 06:09


here's one way to print out a row of <th> tags from a table


NOTE: i didn't test this





$result = mysql_query("select * from table");





for ($i = 0; $i < mysql_num_fields($result); $i++) {


    print "<th>".mysql_field_name($result, $i)."</th>\n";


}





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add a note

mysql_field_seek

mysql_field_len

Last updated: Fri, 28 Nov 2008